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Example 6: design of rectangular beam

design rectangular sections for the beams, loads, and ρ=0.01425. Beam weights are not included in the loads shown.  Assume concrete weighs 150 lb/ft3 , fy= 60,000 psi, and fc'= 4000 psi, unless given otherwise.

Figure 1

Assuming beam weight=0.55k/ft

ultimate dead load=1.2*(0.55+2)=3.06 k/ft

ultimate live load=1.6*20=32k

the ultimate moment from figure 2

Mu=604.32k-ft=7,251,840 lb-in
Figure 2


bd^2=Mu/Ф*ρ*fy*(1-ρ*fy/(1.7fc')) assuming Ф=0.90



trail and error selecting   bxd=20x22.5

beam dimension=20inx26in

checking beam weight=20*26*150/(144*1000)=0.541 k/ft    ok

As=ρ*b*d=0.01425*20*22.5=6.40 in2

using 7#9 placed at top because the moment is positive

As=7*1=7 in2

checking if ρ>ρmin

ρmin=3* fc'/fy and not less than 200/fy

ρmin=3* 4000/60000 and not less than 200/60000
ρmin=0.00316 and 0.00333     ok

checking if Ф=0.9 valid or no



β1=0.85 for fc'=4000 psi or less




εt=0.003*(22.5)/7.27-0.003=0.0063>0.005 so section is tension control Ф=0.9  is ok

checking if ФMn>Mu

ФMn=0.9*7.0*60,000*(22.5-6.17/2)=7,338,870 lb-in>Mu   ok


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